Isotherms of carbon dioxide at various temperatures are repersented in figure. Answer the following questions based on this figures.

(i) In which state will `CO_(2)` exist between the points a and b at temperature `T_(1)` ?
(ii) At what point will `CO_(2)` start liquefyinh when temperature is `T_(1)` ?
(iii) At what point will `CO_(2)` be completely liquefued when temperature is `T_(2)` ?
(iv) Will condensation take place when the temperature is `T_(3)` ?
(v) What portion of the isotherm at `T_(1)` represent liquid and gaseous `CO_(2)` at equilibrium ?

Explanation

Given
Average speed=Most proable speed
`=9xx10^(-4)cm s^(-1)` or `9xx10^(2)m s^(-1)`
We know,
Average speed `=sqrt((8RT)/(pi M))` (`i`)
and most probable speed `=((2RT)/(M))` (`ii`)
Equating equations (`i`) and (`ii`), we get
`9xx10^(2)=sqrt((8xx8.314xxT_(1))/(3.14xx44xx10^(-3)))`
or `T_(1)=1682.5 K`
and `9xx10^(2)=sqrt((2xx8.314xxT_(2))/(44xx10^(-3)))`
or `T_(2)=2143.4 K`