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Calculate the temperature at which the r...

Calculate the temperature at which the root mean square velocity, the average velocity, and the most proable velocity of oxygen gas are all equal to `1500 m s^(-1)`.

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To solve the problem of calculating the temperature at which the root mean square velocity, the average velocity, and the most probable velocity of oxygen gas are all equal to 1500 m/s, we will use the following formulas: 1. **Root Mean Square Velocity (RMS)**: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] 2. **Average Velocity (v_avg)**: ...
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CENGAGE CHEMISTRY ENGLISH-STATES OF MATTER-Exercises (Ture False)
  1. Calculate the temperature at which the root mean square velocity, the ...

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  2. In the van der Waals equation (P + (n^(2)a)/(V^(2)))(V - nb) = nRT ...

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  3. Kinetic energy of a molecule is zero at 0^(@)C

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  4. Gas in a closed container will exert much higher pressure due to gravi...

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  5. The graph between PV vs P at constant temperature is linear parallel t...

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  6. Real gases show deviation from ideal behavior at low temperature and h...

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  7. All the molecules in a given sample of gas move with same speed.

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  8. Small value of a means, gas can be easily liqueifed.

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  9. Small value of a means, gas can be easily liqueifed.

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  10. Rate of diffusion is directly proportional to the square root of molec...

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  11. For ideal gases, Z = 1 at all temperature and pressure.

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  12. According to charles's law,

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  13. The pressure of moist gas is higher than pressure of dry gas.

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  14. Gases do not occupy volume and do not have force of attraction.

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  15. The van der Waal equation of gas is (P + (n^(2)a)/(V^(2))) (V - nb)...

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  16. Surface tension and surface energy have different dimensions.

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  17. The plot of PV vs P at particular temperature is called isovbar.

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  18. Give reasons for the following in one or two sentences. (a) A bottle...

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  19. Can a gas with a = 0 be liquefied?

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  20. The van der waals constants have same values for all the gases.

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  21. All the molecules in a given sample of gas move with same speed.

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