Two flasks `A` and `B` of equal volume containing equal masses of `H_(2)` & `CH_(4)` gases are at `100 K` and `200 K` temperature, respectively. Which of the following is true about the total `KE` (Kinetic energy)?

Options

A. Total `KE` of `H_(2)` is four times that of `CH_(4)`.
B. Total `KE` of `CH_(4)` is four times that of `H_(2)`.
C. Total `KE` of `H_(2)` is two times that of `CH_(4)`.
D. Total `KE` of `CH_(4)` is two times that of `H_(2)`.

Explanation

To solve the problem, we need to determine the total kinetic energy (KE) of the gases in two flasks, A and B, containing equal masses of \( H_2 \) (hydrogen) and \( CH_4 \) (methane) at different temperatures.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Flask A: Contains \( H_2 \) gas at \( 100 \, K \)
- Flask B: Contains \( CH_4 \) gas at \( 200 \, K \)
- Equal masses of gases in both flasks.
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