`20 mol` of chlorine gas occupies a volume of `800 mL` at `300 K` and `5xx10^(6) Pa` pressure. Calculate the compressibility factor of the gas. `(R=0.083 L "bar" K^(-1)mol^(-1))`. Comment, whether the gas is more compressible or less compressible under these conditions.

Explanation

To calculate the compressibility factor (Z) of chlorine gas under the given conditions, we will follow these steps:

### Step 1: Use the Ideal Gas Law
The ideal gas law is given by the equation:
\[ PV = nRT \]
Where:
- \( P \) = pressure (in bar)
- \( V \) = volume (in liters)
...