The internal pressure loss of `1 mol` of van der Waals gas over an ideal gas is equal to

Options

A. Zero
B. `b^(2)`
C. `(a)/(V^(2))`
D. `b-(a)/(RT)`

Explanation

To find the internal pressure loss of 1 mole of van der Waals gas compared to an ideal gas, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Van der Waals Equation**:
The van der Waals equation for 1 mole of gas is given by:
\[
\left(P + \frac{a}{V^2}\right)(V - b) = RT
...