A given volume of oxygen containing `20%` by volume of ozone required `175s` to effuse when an equal volume of oxygen took `167s` only, under similar conditions. Find the density of ozone.

Explanation

To solve the problem, we will use Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its density. We will follow these steps:

### Step 1: Understand the problem
We have a mixture of oxygen (O2) and ozone (O3) where the volume of ozone is 20% of the total volume. The time taken for the effusion of the mixture is 175 seconds, while pure oxygen takes 167 seconds.

### Step 2: Apply Graham's Law
According to Graham's law, the ratio of the rates of effusion of two gases is given by:

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