`127 mL` of a certain gas diffuses in the same time as `100 mL` of chlorine under the same conditions. Calculate the molecular weight of the gas.

Explanation

To solve the problem of calculating the molecular weight of the gas that diffuses in the same time as chlorine, we can use Graham's law of effusion and diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass (molecular weight).

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Volume of the gas (V1) = 127 mL
- Volume of chlorine (V2) = 100 mL
- Molecular weight of chlorine (M2) = 71 g/mol
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