Two flasks ‘A’ and B’ have equal volumes. Flask ‘A’ contains `H_(2)` and is maintained at 300 K while ‘B’ contains equal mass of `CH_(4)` gas and is maintained at 600 K. Which flask contains greater number of molecules? How many times more?

Options

A. `A`
B. `B`
C. Both `A` and `B`
D. None

Explanation

Let `n_(A)` be the amount of `H_(2)` and `n_(B)` be the amount the `CH_(4)`.
We know that
`n_(A)=(m)/(2)`, `n_(B)=(m)/(16)`
where `m` is the mass of the gas of two flasks `A` and `B`
`:. (n_(A))/(n_(B))=(m)/(2)//(m)/(16)=8`
Now, the number of molecules in these flasks are given as
`N_(A)=(m)/(2).N`, `N_(B)=(m)/(16)N`,
where `N` is Avogadro's constant.
`:. (N_(A))/(N_(B))=8`
`implies N_(A)gtN_(B)`