Two gaseous molecules `A` and `B` are traveling towards each other. Let the mean free path of the molecule be `sigma` and `Z` be the collision number with other molecules at pressure `1 atm`. Answer the following questions
If the mean free path is `sigma` at `1 atm` pressure, then its value at `5 atm` pressure is

Options

A. `5sigma`
B. `(2)/(5)sigma`
C. `(sigma)/(5)`
D. None

Explanation

To find the mean free path of a molecule at a pressure of 5 atm, we can use the relationship between mean free path and pressure. The mean free path (σ) is inversely proportional to the pressure (P).

### Step-by-Step Solution:

1. **Understand the Relationship**: The mean free path (σ) is inversely proportional to the pressure (P). This can be expressed mathematically as:
\[ \sigma \propto \frac{1}{P} \]
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