X mL Hydrogen gas effuses through a hole in a container in `5 s`. The time taken for the effusion of the same volume of the gas specified below under identical conditions is

Options

A. `10 s: He`
B. `20s: O_(2)`
C. `25s: CO`
D. `55s: CO_(2)`

Explanation

To solve the problem of determining the time taken for the effusion of a specified gas under identical conditions, we will use Graham's law of effusion. This law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

### Step-by-Step Solution:

1. **Understand Graham's Law of Effusion**:
\[ \text{Rate of effusion} \propto \frac{1}{\sqrt{M}} \]
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