If `10 g` of a gas at 1 atmospheric pressure is cooled from `273^(@)C` to `0^(@)C`, keeping the volume constant, its pressure would become

Options

A. `1//273 atm`
B. `2 atm`
C. `(1)/(2)atm`
D. 273 atm

Explanation

To solve the problem, we will use Gay-Lussac's Law, which states that the pressure of a gas is directly proportional to its absolute temperature when the volume is held constant. The formula for Gay-Lussac's Law is:

\[ \frac{P_1}{T_1} = \frac{P_2}{T_2} \]

### Step-by-step Solution:

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