The compressibility factor of a gas is greater than unity at `STP`. Therefore

Options

A. `V_(m)gt22.4 L`
B. `V_(m)lt22.4 L`
C. `V_(m)=22.4 L`
D. The gas will become less liquefiable

Explanation

To solve the problem, we need to analyze the implications of the compressibility factor (Z) being greater than unity at standard temperature and pressure (STP).

### Step-by-Step Solution:

1. **Understanding the Compressibility Factor (Z)**:
- The compressibility factor (Z) is defined as \( Z = \frac{PV}{nRT} \), where:
- \( P \) = pressure,
- \( V \) = volume,
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