A `3:2` molar mixture of `N_(2)` and `CO` is present in a vessel at `500 "bar"` pressure. Due to hole in the vessel, the gas mixture leaks out. The composition of mixture effusing out initially is

Options

A. `n_(N_(2)):n_(CO): : 1:2`
B. `n_(N_(2)):n_(CO): : 6:1`
C. `n_(CO):n_(N_(2)): : 1:2`
D. `n_(CO):n_(N_(2)): : 2:3`

Explanation

To solve the problem of determining the composition of the gas mixture effusing out of a vessel containing a `3:2` molar mixture of `N2` and `CO` at `500 bar` pressure, we can follow these steps:

### Step 1: Determine the partial pressures of N2 and CO
Given that the molar ratio of N2 to CO is `3:2`, we can calculate the partial pressures of each gas based on the total pressure.

1. Total moles = 3 (N2) + 2 (CO) = 5 moles
2. Molar fraction of N2 = 3/5
3. Molar fraction of CO = 2/5
...