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1.0 litre of N(2) and 7/8 litre of O(2) ...

1.0 litre of `N_(2)` and 7/8 litre of `O_(2)` at the same temperature and pressure were mixed together. What is the relation between the masses of the two gases in the mixture ?

A

`M_(N_(2))=3M_(O_(2))`

B

`M_(N_(2))=8M_(O_(2))`

C

`M_(N_(2))=M_(O_(2))`

D

`M_(N_(2))=16M_(O_(2))`

Text Solution

Verified by Experts

`PV=(M)/(m)RT`
`Pxx1=(M_(N_(2)))/(28)RT`
`Pxx(7)/(8)=(M_(O_(2)))/(32)RT`
Dividing equation (`i`) by (`ii`), we get
`M_(N_(2))=M_(O_(2))`
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