Equal weights of methane and hydrogen are mixed in an empty container at `25^(@)C`. The fraction of the total pressure exerted by hydrogen is

Options

A. `(1)/(2)`
B. `(8)/(9)`
C. `(1)/(9)`
D. `(16)/(17)`

Explanation

Let `16 g` of both be mixed.
Mole of `H_(2)=(16)/(2)=8`
Mole of `CH_(4)=(16)/(16)=1`
Mole fraction of `H_(2)=(8)/(1+8)=(8)/(9)`
Which is also the fraction of total pressure executed by `H_(2)`.