The average veloctiy of an ideal gas molecule at `27^(@)C` is `0.3 m s^(-1)`. The average velocity at `927^(@)C` will be

Options

A. `0.6 m s^(-1)`
B. `0.3 m s^(-1)`
C. `0.9 m s^(-1)`
D. `3.0 m s^(-1)`

Explanation

To solve the problem of finding the average velocity of an ideal gas molecule at `927°C`, given that the average velocity at `27°C` is `0.3 m/s`, we can follow these steps:

### Step-by-step Solution:

1. **Identify Given Values:**
- Average velocity at `T1 = 27°C` (V1) = `0.3 m/s`
- Temperature `T1 = 27°C`
- Temperature `T2 = 927°C`
...