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According to Graham's law, at a given te...

According to Graham's law, at a given temperature the ratio of diffusion `r_A/r_B` of gases A and B is given by
(where P and M are pressures and molecular weights of gases A and B respectively)

A

`((P_(A))/(P_(B)))((M_(A))/(M_(B)))^(1//2)`

B

`((M_(A))/(M_(B)))((P_(A))/(P_(B)))^(1//2)`

C

`((P_(A))/(P_(B)))((M_(B))/(M_(A)))^(1//2)`

D

`((M_(A))/(M_(B)))((P_(B))/(P_(A)))^(1//2)`

Text Solution

Verified by Experts

Rate of diffusion is directly proportional to the pressure and inversely propotional to the molar mass of the gas.
Hence,
`(r_(A))/(r_(B))=(P_(A))/(P_(B))((M_(B))/(M_(A)))^(1//2)`
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