3.7 g of a gas at 25°C occupies the same volume as 0.184 g of hydrogen at 17°C and at the same pressure. What is the molecular mass of the gas ?

Explanation

`PV=nRT`
`P` and `V` are the same.
So, `n_(1)T_(1)=nT_(2)`
or `(w_(1))/(M_(1))T_(1)=(w_(2))/(M_(2))T_(2)`
or `(3.7)/(M_(1))xx298=(0.184)/(2)xx290`
or `M_(1)=41.33 g`