The composition of the equilibrium mixture (`Cl_(2)` `2Cl`) , which is attained at `1200^(@)C`, is determined by measuring the rate of effusion through a pin hole. It is observed that a `1.80 mm Hg` pressure, the mixture effuses `1.16 times` as fact as krypton effuses under the same conditions. Calculate the fraction of chlorine molecules dissociated into atoms (atomic weight of `Kr` is `84`).

Explanation

`(r )/(r_(kr))=sqrt((M_(w)(Kr))/(M))`
`1.16=sqrt((83.8)/(M)) :. M=62.28`
(Molar weight of `Cl_(2)` and mixture `=62.28`)

Total moles `=1-x+2x=1+x`
`:. (2x+(35.5)+(1-x)xx71)/(1+x)=62.28`
`(71)/(1+x)=62.28`
`x=0.14=14%` dissociated