400 mL of `N_(2)` gas at 700 mm and 300 mL of `H_(2)` gas at 800 mm are introduced into a vessel of 2 L at the same temperature. Calculate the final pressure of the gas mixture.

Explanation

Final volume `=1.5L+2.0L=3.5L`
for partial pressure of `H_(2)`
`P_(1)V_(1)=P_(2)V_(2)`
`750xx1.5=P_(2)xx3.5` ltbr. Or `p_(H_(2))=(750xx1.5)//3.5=321.43mm`
for partial pressure of `O_(2)`
`P_(1)'V_(1)'=P_(2)'V_(2)'`
`100xx2=P_(2)'xx3.5`
or `p_(O_(2))=(100xx2)//3.5=57.14mm`
`thereforeP_("mixture")=321.43+57.14=378.57mm`