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At room temperature, ammonia gas at 1 at...

At room temperature, ammonia gas at `1 atm` pressure and hydrogen chloride gas at `P atm` pressure are allowed to effuse through identical pin holes from opposite ends of a glass tube of `1 m` length and of uniform cross- section. Ammonium chloride is first formed at a distance of `60 cm` from the end through which `HCl` gas is sent in. What is the value of `P`?

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To solve the problem, we will use Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. The formula can be expressed as: \[ \frac{R_{HCl}}{R_{NH3}} = \frac{P_{HCl}}{P_{NH3}} \cdot \sqrt{\frac{M_{NH3}}{M_{HCl}}} \] Where: - \( R_{HCl} \) and \( R_{NH3} \) are the rates of diffusion of HCl and NH3 respectively. ...
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At room temperature, ammonia gas at 1 atm pressure and hydrogen chloride gas at P atm pressure are allowed to effuse through identical pin holes from opposite ends of a glass tube of one metre length and of uniform cross section. Ammonium chloride is first formed at a distance of 60 cm from the end through which HCl gas is sent in. What is the value of P?

Through the two ends of a glass tube of length 200cm hydrogen chloride gas and ammonia are allowed to enter At what distance ammonium chloride will first appear ? .

X and Y are two volatile liquids with molar weights of 10gmol^(-1) and 40gmol^(-1) respectively. Two cotton plugs, one soaked in X and the other soaked in Y , are simultaneously placed at the ends of a tube of length L=24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atm pressure and a temperature of 300K . Vapours of X and Y react to form a product whichh is first observed at a distance d cm from the plug soaked in X . Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and two vapours. The value of d in cm (shown in figure), as estimated from Graham's law, is

X and Y are two volatile liquids with molar weights of 10gmol^(-1) and 40gmol^(-1) respectively. Two cotton plugs, one soaked in X and the other soaked in Y , are simultaneously placed at the ends of a tube of length L=24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atm pressure and a temperature of 300K . Vapours of X and Y react to form a product whichh is first observed at a distance d cm from the plug soaked in X . Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and two vapours. The value of d in cm (shown in figure), as estimated from Graham's law, is

Torricelli was the first do devise an experiment for measuring atmospheric pressure . He took calibrated hard glass tube , 1 m in lengt and of uniform cross section , closed at one end . He filled the whole tube with dry mercury taking care than no air or water droplets remain inside the tube , closed the opposite end of the tube tightly with thumb and inverted it . He put this inverted mercury tube into a mercury through , taking care that the end of the tube remains inside the mercury through , An interesting thing was noticed . Mercury in the tube fell down at first and then stopped at a particular position . The height was 76 cm above the free surface of mercury in the through . When the given tube was inclined or lowered in the mercury trough , the vertical haight of mercury level in the tube was always found constant . Torricelli explained this by saying that the free surface of mercury in the trough . Hence , the hydrostatic pressure exerted by the trough measures the atmospheric pressure . If an additional hole is also made at P ' at the top point of the tube , then A. mercury will not come out of the tube B. mercury may come out of the tube after some time . C. mercury will come out of the tube instantly D. none of these

Torricelli was the first do devise an experiment for measuring atmospheric pressure . He took calibrated hard glass tube , 1 m in lengt and of uniform cross section , closed at one end . He filled the whole tube with dry mercury taking care than no air or water droplets remain inside the tube , closed the opposite end of the tube tightly with thumb and inverted it . He put this inverted mercury tube into a mercury through , taking care that the end of the tube remains inside the mercury through , An interesting thing was noticed . Mercury in the tube fell down at first and then stopped at a particular position . The height was 76 cm above the free surface of mercury in the through . When the given tube was inclined or lowered in the mercury trough , the vertical haight of mercury level in the tube was always found constant . Torricelli explained this by saying that the free surface of mercury in the trough . Hence , the hydrostatic pressure exerted by the trough measures the atmospheric pressure . If this expriment uses water instead of mercury , then A. length of water will be equal to 76 cm B. length of water will be less than 76 cm C. length of water will be greater than 76 cm D. none of the above

Torricelli was the first do devise an experiment for measuring atmospheric pressure . He took calibrated hard glass tube , 1 m in lengt and of uniform cross section , closed at one end . He filled the whole tube with dry mercury taking care than no air or water droplets remain inside the tube , closed the opposite end of the tube tightly with thumb and inverted it . He put this inverted mercury tube into a mercury through , taking care that the end of the tube remains inside the mercury through , An interesting thing was noticed . Mercury in the tube fell down at first and then stopped at a particular position . The height was 76 cm above the free surface of mercury in the through . When the given tube was inclined or lowered in the mercury trough , the vertical haight of mercury level in the tube was always found constant . Torricelli explained this by saying that the free surface of mrcury in the trough . Hence , the hydrostatic pressure exerted by the trough measures the atmospheric pressure . If a small hole is made at point P in the barometer tube , then

The density of the vapour of a substance at 1 atm pressure and 500 K is 0.36 kg m^(-3) . The vapour effuses through a small hole at a rate of 1.33 times faster than oxygen under the same condition. Determine, (a) molecular weight (b) molar volume (c) compression factor (Z) of the vapour and (d) which forces among the gas molecules are dominating, the attractive or the repulsive?

16 mL of He gas effuses through a pin hole in 4 sec from a container having P_(He) equal to 1 atm. If same container is filled with CH_(4) having pressure 2 atm, how much volume (in mL) of CH_(4) will be leaked through same pin hole in 2 sec?

In the given figure, atmospheric pressure p_0 = 1 atm and mercury column length is 9 cm. Pressure p of the gas enclosed in the tube is

CENGAGE CHEMISTRY ENGLISH-STATES OF MATTER-Ex 5.3
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