The volumes of ozone and chlorine diffusing in the same time are `35 mL` and `29mL`, respectively. If the molecular weight of chlorine is `71`, calculate the molecular weight of ozone.

Explanation

To solve the problem, we will use Graham's law of effusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Volume of ozone (V1) = 35 mL
- Volume of chlorine (V2) = 29 mL
- Molecular weight of chlorine (M2) = 71 g/mol
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