The average velocity of `CO_(2)` at the temperature `T_(1)K` and maximum (most) proable velocity of `CO_(2)` at the temperature `T_(2) K` is `9xx10^(4) cm s^(-1)`. Calculate the values of `T_(1)` and `T_(2)`.

Explanation

To solve the problem, we need to calculate the temperatures \( T_1 \) and \( T_2 \) using the given velocities of carbon dioxide (\( CO_2 \)) at those temperatures.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Average velocity of \( CO_2 \) at temperature \( T_1 \) is \( 9 \times 10^4 \, \text{cm/s} \).
- Most probable velocity of \( CO_2 \) at temperature \( T_2 \) is also \( 9 \times 10^4 \, \text{cm/s} \).
- Convert the velocity to SI units:
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