20 mol of chlorine gas occupies a volume of 800 ml at 300 K and `5 xx 10^(6)` Pa pressure. Calculate the compressibility factor of the gas (R = 0.083 L bar `K^(-1) mol^(-1)`). Comment whether the gas is more compressible or less compressible under the conditions

Explanation

To calculate the compressibility factor (Z) of chlorine gas under the given conditions, we will follow these steps:

### Step 1: Write the formula for the compressibility factor
The compressibility factor (Z) is given by the formula:
\[ Z = \frac{PV}{nRT} \]
where:
- \( P \) = pressure
- \( V \) = volume
...