The enthalpy of combustion of benzoic acid `(C_(6)H_(5)COOH)` at `298K` and `1atm` pressure is `-2500.0 kJ mol^(-1)`. What is `DeltaU` for the reaction?

Explanation

To find the change in internal energy (\( \Delta U \)) for the combustion of benzoic acid, we can use the relationship between enthalpy change (\( \Delta H \)) and internal energy change (\( \Delta U \)) given by the equation:

\[ \Delta H = \Delta U + \Delta N_g R T \]

where:
- \( \Delta H \) is the enthalpy change,
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