A swimmer coming out from a pool is covered with a film of water weighing about `80g`. How much heat must be supplied to evaporate this water ? If latent heat of evaporation for `H_(2)O` is `40.79 kJ mol^(-1)` at `100^(@)C`.

Explanation

To solve the problem of how much heat must be supplied to evaporate 80 grams of water, we will follow these steps:

### Step 1: Determine the number of moles of water
To find the number of moles, we use the formula:
\[ \text{Number of moles} = \frac{\text{mass of water (g)}}{\text{molar mass of water (g/mol)}} \]
The molar mass of water (H₂O) is approximately 18 g/mol. Therefore:
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