`10mol` of an ideal gas confined to a volume of `10L` is released into atmosphere at `300K` where the pressure is 1bar. The work done by the gas is `(R = 0.083 L "bar" K^(-1)mol^(-1))`

Options

A. `249 L`bar
B. `259 L` bar
C. `239 L`bar
D. `220L` bar

Explanation

To find the work done by the gas when it expands into the atmosphere, we can follow these steps:

### Step 1: Understand the situation
We have 10 moles of an ideal gas initially confined to a volume of 10 L. The gas is released into the atmosphere at a constant pressure of 1 bar and a temperature of 300 K.

### Step 2: Use the ideal gas equation
The ideal gas law is given by:
\[ PV = nRT \]
...