The enthalpy of vaporisation of benzene `(C_(6)H_(6))` is `30.8 kJ mol^(-1)` at its boiling point `(80.1^(@)C)`. Calculate the entropy change in going from:
a. liquid to vapour and
b. vapour to liquid at `80.1^(@)C`.

Explanation

To solve the problem, we need to calculate the entropy change for two processes involving benzene (C₆H₆) at its boiling point (80.1°C).

### Given:
- Enthalpy of vaporization (ΔH_vaporization) = 30.8 kJ/mol
- Boiling point (T_b) = 80.1°C

### Step 1: Convert ΔH_vaporization to Joules
Since entropy is typically expressed in Joules, we need to convert the enthalpy of vaporization from kJ to J.
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