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Calculate the change in entropy for the ...

Calculate the change in entropy for the following reaction
`2CO(g) +O_(2)(g) rarr 2CO_(2)(g)`
Given:
`S_(CO)^(Theta)(g)=197.6 J K^(-1)mol^(-1)`
`S_(O_(2))^(Theta)(g)=205.03 J K^(-1)mol^(-1)`
`S_(CO_(2))^(Theta)(g)=213.6 J K^(-1)mol^(-1)`

Text Solution

Verified by Experts

For the reaction
`4Fe(s) +3O_(2)(g) rarr 2Fe_(2)O_(3)(s)`
`Delta_(r)S_(m)^(Theta) = 2S_(m)^(Theta) (Fe_(2)O_(3)) - [4 xx S_(m)^(Theta) (Fe) +3 xxS_(m)^(Theta) (O_(2))]`
`= 2 xx 87.4 - [4 xx 27.3 +3 xx 205.0]`
`=- 549.4 J K^(-1)mol^(-1)`
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