Calculate the entropy change at `298K` for the reaction
`Br_(2)(l) +CI_(2)(g) rarr 2BrCI(g)`
`DeltaH = 29.3 kJ at 298K`. The entropies of `Br_(2)(l), CI_(2)(g)`, and `BrCI(g)` at the above temperature and `152.3, 223.0` and `239.7 J mol^(-1)K^(-1)` respectively.

Explanation

To calculate the entropy change (ΔS) for the reaction:

\[ \text{Br}_2(l) + \text{Cl}_2(g) \rightarrow 2 \text{BrCl}(g) \]

at 298 K, we will follow these steps:

### Step 1: Write down the given data
- Entropy of \( \text{Br}_2(l) \): \( S^\circ(\text{Br}_2) = 152.3 \, \text{J mol}^{-1} \text{K}^{-1} \)
...