For the reaction,
`N_(2)(g) +3H_(2)(g) rarr 2NH_(3)(g)`
`DeltaH =- 95.0 kJ` and `DeltaS = - 19000 J K^(-1)`
Calculate the temperature in centigrade at which it will attain equilibrium.

Explanation

To solve the problem, we need to find the temperature at which the reaction reaches equilibrium using the given values of enthalpy change (ΔH) and entropy change (ΔS). The reaction is:

\[ N_{2}(g) + 3H_{2}(g) \rightarrow 2NH_{3}(g) \]

Given:
- ΔH = -95.0 kJ
- ΔS = -19000 J K\(^{-1}\)

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