The equilibrium constant at `25^(@)C` for the process:
`CO^(3+) (aq) +6NH_(3)(aq) hArr[Co(NH_(3))_(6)]^(3+)(aq)` is `2 xx 10^(7)`.
Calculate the value of `DeltaG^(Theta)` at `25^(@)C at 25^(@)C[R = 8.314 J K^(-1)mol^(-1)]`.
In which direction the reaction is spontaneous when the recatants and proudcts are in standard state?

Explanation

To solve the problem, we need to calculate the standard Gibbs free energy change (ΔG°) for the reaction given the equilibrium constant (K) at 25°C. We will also determine the direction of spontaneity for the reaction when the reactants and products are in their standard states.

### Step-by-Step Solution:

1. **Convert Temperature to Kelvin:**
- The temperature given is 25°C. To convert this to Kelvin, we use the formula:
\[
T(K) = T(°C) + 273.15
...