The equilibrium constant for the reaction
`CO_(2)(g) +H_(2)(g) hArr CO(g) +H_(2)O(g) at 298 K` is `73`. Calculate the value of the standard free enegry change `(R =8.314 J K^(-1)mol^(-1))`

Explanation

To calculate the standard free energy change (ΔG°) for the reaction given the equilibrium constant (K) and the temperature, we can use the following relationship:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Equilibrium constant (K) = 73
- Temperature (T) = 298 K
- Universal gas constant (R) = 8.314 J K⁻¹ mol⁻¹
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