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Calculate equilibrium constant for the reaction given below at `400K`, if `DeltaH^(Theta) = 77.2 kJ mol^(-1)` and `DeltaS^(Theta) = 122 J K^(-1) mol^(-1)`
`PCI_(5)(g) rarr PCI_(3)(g) +CI_(2)(g)`

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To calculate the equilibrium constant \( K \) for the reaction \[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \] at \( 400 \, K \), given that \( \Delta H^\circ = 77.2 \, kJ \, mol^{-1} \) and \( \Delta S^\circ = 122 \, J \, K^{-1} \, mol^{-1} \), we will follow these steps: ...
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Calculate the equilibrium constnat for the reaction given below at 400K , if DeltaH^(Theta) = 77.2 kJ "mole"^(-1) and DeltaS^(Theta) = 122 J K^(-1) "mole"^(-1) . PCI_(5)(g) rarr PCI_(3)(g) +CI_(2)(g)

What is the equilibrium constant K_(c) for the following reaction at 400K ? 2NOCI(g) hArr 2NO(g) +CI_(2)(g) DeltaH^(Theta) = 77.2 kJ mol^(-1) and DeltaS^(Theta) = 122 J K^(-1) mol^(-1) at 400K .

Calculate the value of equilibrium constant, K for the following reaction at 400 K. 2NOCl(g) hArr 2NO (g) + Cl_2(g) DeltaH^@ = 80.0 kJ mol^(-1), DeltaS^@ = 120 KJ^(-1) mol^(-1) at 400 K, R = 8.31 JK^(-1) mol^(-1) .

Calculate the standard free energy change for the reaction: H_(2)(g) +I_(2)(g) rarr 2HI(g), DeltaH^(Theta) = 51.9 kJ mol^(-1) Given: S^(Theta) (H_(2)) = 130.6 J K^(-1) mol^(-1) , S^(Theta) (I_(2)) = 116.7 J K^(-1) mol^(-1) and S^(Theta) (HI) = 206.8 J K^(-1) mol^(-1) .

Calculate the standard free energy change for the reaction: H_(2)(g) +I_(2)(g) rarr 2HI(g), DeltaH^(Theta) = 51.9 kJ mol^(-1) Given: S^(Theta) (H_(2)) = 130.6 J K^(-1) mol^(-1) , S^(Theta) (I_(2)) = 116.7 J K^(-1) mol^(-1) and S^(Theta) (HI) =- 206.8 J K^(-1) mol^(-1) .

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Calculate equilibrium constant for the reaction: 2SO_(2)(g) +O_(2)(g) hArr 2SO_(3)(g) at 25^(@)C Given: Delta_(f)G^(Theta) SO_(3)(g) = - 371.1 kJ mol^(-1) , Delta_(f)G^(Theta)SO_(2)(g) =- 300.2 kJ mol^(-1) and R = 8.31 J K^(-1) mol^(-1)

Calculated the equilibrium constant for the following reaction at 298K : 2H_(2)O(l) rarr 2H_(2)(g) +O_(2)(g) Delta_(f)G^(Theta) (H_(2)O) =- 237.2 kJ mol^(-1),R = 8.314 J mol^(-1) K^(-1)

For the reaction, 4C(graphite) +5H_(2)(g) rarr nC_(4)H_(10)(g) , DeltaH^(Theta) =- 124.73 kJ mol^(-1), DeltaS^(Theta) =- 365.8 J K^(-1) mol^(-1) 4C(graphite) +5H_(2)(g) rarr iso-C_(4)H_(10)(g) DeltaH^(Theta) =- 131.6 kJ mol^(-1), DeltaS^(Theta) =- 381.079 J K^(-1) mol^(-1) Indicate whther normal butane can be spontaneously converted to iso-butane or not.

For the reaction, 2NOCl(g) hArr 2NO(g)+Cl_(2)(g) Calculate the standard equilibrium constant at 298 K . Given that the value of DeltaH^(ɵ) and DeltaS^(ɵ) of the reaction at 298 K are 77.2 kJ mol^(-1) and 122 J K^(-1) mol^(-1) .

CENGAGE CHEMISTRY ENGLISH-THERMODYNAMICS-Ex 6.5
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  5. The equilibrium constant at 25^(@)C for the process: CO^(3+) (aq) +6...

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  6. The standard Gibbs energies (Delta(f)G^(Theta)) for the formation of S...

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  7. It is planned to carry out the reaction: CaCO(3)(s) hArr CaO(s) +CO(...

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  8. The equilibrium constant for the reaction CO(2)(g) +H(2)(g) hArr CO(...

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  9. Calculated the equilibrium constant for the following reaction at 298K...

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  10. The equilibrium constant for the reaction: CH(3)COOH(l) +C(2)H(5)OH(...

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  11. Calculate the entropy change for a reaction: XrarrY Given that Del...

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  12. Calculate the equilibrium constant for the following reaction at 298K ...

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  13. For the equilibrium reaction: 2H(2)(g) +O(2)(g) hArr 2H(2)O(l) at 29...

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  14. Calculate equilibrium constant for the reaction given below at 400K, i...

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  15. Calculate equilibrium constant for the reaction: 2SO(2)(g) +O(2)(g) ...

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  16. C(2)H(4) +CI(2) rarr C(2)H(4)CI(2) DeltaH =- 270.6 kJ mol^(-1)K^(-1)...

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  17. Calculate free energy change for the reaction: H(2)(g) + CI(2)(g) ra...

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  18. For the reaction, 4C(graphite) +5H(2)(g) rarr nC(4)H(10)(g), Delt...

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  19. A chemical reaction cannot occur at all if its

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  20. Calculate the standard free energy change for the reaction: H(2)(g)...

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