Calculate equilibrium constant for the reaction:
`2SO_(2)(g) +O_(2)(g) hArr 2SO_(3)(g) at 25^(@)C`
Given: `Delta_(f)G^(Theta) SO_(3)(g) = - 371.1 kJ mol^(-1)`,
`Delta_(f)G^(Theta)SO_(2)(g) =- 300.2 kJ mol^(-1)`
and `R = 8.31 J K^(-1) mol^(-1)`

Explanation

To calculate the equilibrium constant (K) for the reaction:

\[ 2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) \]

at 25°C, we can use the Gibbs free energy change (\(\Delta G^\circ\)) for the reaction. The relationship between \(\Delta G^\circ\) and the equilibrium constant K is given by the equation:

\[
\Delta G^\circ = -RT \ln K
...