`1 mol` of `NH_(3)` gas at `27^(@)C` is expanded under adiabatic condition to make volume `8` times `(gamma=1.33)`. Final temperature and work done, respectively, are

Options

A. `150K, 909 cal`
B. `150K, 400cal`
C. `250K, 100cal`
D. `200K, 800cal`

Explanation

To solve the problem of finding the final temperature and work done during the adiabatic expansion of 1 mole of ammonia gas (NH₃), we will follow these steps:

### Step 1: Convert Initial Temperature to Kelvin
Given the initial temperature \( T_1 = 27^\circ C \):
\[ T_1 = 27 + 273 = 300 \, K \]

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