Carnot's cycle is said to have `25%` efficiency when it operates between `T` (source) and `300K` (sink). Temperature `T` is

Options

A. `300K`
B. `350K`
C. `375K`
D. `400K`

Explanation

To solve the problem, we need to determine the temperature \( T \) (source) for a Carnot cycle that has an efficiency of 25% when operating between this temperature and a sink temperature of 300 K.

### Step-by-step Solution:

1. **Understand the Efficiency Formula**:
The efficiency \( \eta \) of a Carnot engine is given by the formula:
\[
\eta = 1 - \frac{T_1}{T_2}
...