`A (l) overset(1atn)hArr A(g), Delta_(vap)H = 460.6 cal mol^(-1)`, boiling point `-50K`. What is the boiling point at `10` atm

Options

A. `150K`
B. `75 K`
C. `100K`
D. None is correct

Explanation

To find the boiling point of substance A at a pressure of 10 atm, we can use the Clausius-Clapeyron equation, which relates the change in vapor pressure with temperature. The equation is given by:

\[ \log \frac{P_1}{P_2} = -\frac{\Delta H_{vap}}{2.303 R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right) \]

### Step 1: Identify the known values
- \( P_1 = 1 \, \text{atm} \)
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