For hypothetical reversible reaction
`1//2A_(2)(g) +3//2B_(2)(g) rarr AB_(3)(g), DeltaH =- 20 kJ` if standard entropies of `A_(2),B_(2)`, and `AB_(3)` are `60,40` and `50JK^(-1) mol^(-1)` respectively. The above reaction will be equilibrium at

Options

A. (a) `400K`
B. (b) `500K`
C. (c) `250K`
D. (d) `200K`

Explanation

To find the equilibrium temperature for the given reaction, we will follow these steps:

### Step 1: Write the reaction and identify given values
The reaction is:
\[ \frac{1}{2} A_2(g) + \frac{3}{2} B_2(g) \rightleftharpoons AB_3(g) \]
Given:
...