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The bond dissociation energies of X2, Y2...

The bond dissociation energies of `X_2, Y_2 and XY` are in the ratio of `1 : 0.5 : 1. DeltaH` for the formation of XY is -200 kJ mol^(-1)`. The bond dissociation energy of `X_2` will be

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`(1)/(2)X_(2) +(1)/(2)Y_(2) rarr XY, DeltaH = - 100 kJ`
Let the bond dissociation energy of `X_(2),Y_(2)`, and `XY` be
`a: (a)/(2):a` (the given ratio) `kJ mol^(-1)` respectively.
`:. (a)/(2)+(a)/(4) -a = - 100`
`:. A= 400`
`100 x = 400`
`x = 4`
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