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Delta(f)H^(Theta) of hypothetical MgCl i...

`Delta_(f)H^(Theta)` of hypothetical `MgCl` is `-125 kJ mol^(-1)` and for `MgCl_(2)` is `-642 kJmol^(-1)`. The enthalpy of disporportionation of `MgCl is -49x`. Find the value of `x`.

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To find the value of \( x \) in the given problem, we will follow these steps: ### Step 1: Write the formation reactions and their enthalpy changes 1. For the formation of \( \text{MgCl} \): \[ \text{Mg (s)} + \frac{1}{2} \text{Cl}_2 \text{(g)} \rightarrow \text{MgCl (s)} \quad \Delta_f H^\Theta = -125 \, \text{kJ/mol} \] ...
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