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A heated irron block at 127^(@)C loses 3...

A heated irron block at `127^(@)C` loses `300J` of heat to the surroundings which are at a temperature of `27^(@)C`. This process is `0.05x J K^(-1)`. Find the value of `x`.

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To solve the problem, we need to calculate the total entropy change of the system and the surroundings when the heated iron block loses heat. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Given Data - Temperature of the iron block (T_system) = 127°C = 127 + 273 = 400 K - Temperature of the surroundings (T_surroundings) = 27°C = 27 + 273 = 300 K - Heat lost by the iron block (Q_system) = 300 J - Total entropy change is given as 0.05x J/K. ...
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