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The stable state of aggregation of carbo...

The stable state of aggregation of carbon at `298K` and `1atm` pressure is……………

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The stable state of aggregation of sulphur at 298K and 1atm pressure is…………….sulphur.

The standard enthalpy of diamond is zero at 298K and 1 atm pressure.

The conventional standard molar enthalpy of an element in its stable state of aggregation at 298K is taken to be ……………. .

0.562g of graphite kept in a bomb calorimeter in excess of oxygen at 298K and 1 atmospheric pressure was burnt according to the equation, C_(Graph ite)+O_(2(g))rarr CO_(2(g)) durgin the reaction, temperature rises from 298K o 298.89K . If the heat capacity of the calorimeter and its contents is 20.7 kJ//K , what is the enthalpy change for the above reaction at 298K and 1 atm ?

Henry's law constant for the solubility of nitrogen gas in water at 298 K is 1.0 xx 10^(-5) atm . The mole fraction of nitrogen in air is 0.8 .The number of moles of nitrogen from air dissolved in 10 mol of water at 298 K and 5 atm pressure is

The Henry's law constant for the solubility of N_(2) gas in water at 298K is 1.0 xx 10^(5) atm. The mole fraction of N_(2) in air is 0.8 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298K and 5 atm pressure is

Calculate the equilibrium constant for the following reaction at 298K and 1 atmospheric pressure: C(grap hite) +H_(2)O(l) rarr CO(g) +H_(2)(g) Given Delta_(f)H^(Theta) at 298 K for H_(2)O(l) =- 286.0 kJ mol^(-1) for CO(g) =- 110.5 kJ mol^(-1) DeltaS^(Theta) at 298K for the reaction = 252.6 J K^(-1) mol^(-1)

1g of graphite is burnt in a bomb calorimeter in excess of oxygen at 298 K and 1 atmospheric pressure according to the equation C (graphite) +O_(2)(g)rarrCO_(2)(g) During the reaction, temperature rises from 298 K to 299 K. If the heat capacity of the bomb calorimeter is 20.7kJ/K, what is the enthalpy change for the above reaction at 298 K and 1 atm?

The heat of formation is the change in enthalpy accompanying the formation of a substance fiom its elements at 298 K and 1 atm pressure. Since the anthalpies of elements are taken to be zero, the heat of formation (triangleH) of compounds

The osmotic pressure of 5% solution of urea at 298 K is

CENGAGE CHEMISTRY ENGLISH-THERMODYNAMICS-Exercises (Fill In The Blanks)
  1. The enthalpy change of the reaction: CuSO(4)(s) +5H(2)O(l)rarr CuSO(...

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  2. The enthalpy change when 1mol of graphite is converted into diamond is...

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  3. The stable state of aggregation of carbon at 298K and 1atm pressure is...

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  4. The stable state of aggregation of sulphur at 298K and 1atm pressure i...

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  5. The part of the universe chosen for study of enegry changes is called ...

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  6. The energy stored within a substance is called its…………..

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  7. A reaction in which heat is absorbed is called an……………….

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  8. The enthalpy of elements in their standard states are taken as zero .T...

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  9. Why is heat of neutralisation for a strong acid and strong base consta...

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  10. Delta("sub")H=………………..+………………. .

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  11. The heat of combustion of benzene is -3264 kJmol^(-1). The heat evolve...

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  12. A process which can take place by itself or by initiation is called a…...

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  13. For a process to be spontaneous at constant T and P :

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  14. An endothermic process is non-spontaneous at some temperature . It ca...

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  15. Coal and petrolem are called……………..fuels.

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  16. In an endothermic reaction, the total enthalpy of reactant is………………tha...

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  17. H(2)(g)+(1)/(2)O(2)(g)rarrH(2)O(l), DeltaH =- 286 kJ 2H(2)(g)+O(2)(g...

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  18. C(4)H(10)+(13)/(2)O(2)(g)rarr4CO(2)(g)+5H(2)O(l), DeltaH =- 2878 kJ ...

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  19. HCI +NaOH rarr NaCI +H(2)O, DeltaH =- 57.1 kJ mol^(-1) DeltaH is the...

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  20. C(s) to C(g) , DeltaH = 716.7 kJ DeltaH is the heat of …………… of gr...

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