`HCI +NaOH rarr NaCI +H_(2)O, DeltaH =- 57.1 kJ mol^(-1)`
`DeltaH` is the heat of ……………….of `HCI` and `NaOH` solution.

H_(2)O(l) rarr H_(2)O(s), DeltaH =- 6.01 kJ DeltaH is the heat of ……………….of water.

H_(2)O(s) rarr H_(2)O(l), DeltaH = 6.01 kJ DeltaH is the heat of …………………of ice.

H_(2)O(g) rarr H_(2)O(l), DeltaH =- 40.7 kJ DeltaH is the heat of……………….of water.

H_(2)O(l) rarr H_(2)O(g), DeltaH = +40.7 kJ DeltaH is the heat of ……………..of water.

CsOH +HCI rarr CsCI +H_(2)O, DeltaH =- 13.4 kcal mol^(-1)……….(i) CsOH +HF rarr CsF +H_(2)O, DeltaH =- 16.4 kcal mol^(-1) ………(ii) Calculate DeltaH for the ionisation of HF in H_(2)O .

CsOH +HCI rarr CsCI +H_(2)O, DeltaH =- 13.4 kcal mol^(-1)……….(i) CsOH +HF rarr CsF +H_(2)O, DeltaH =- 16.4 kcal mol^(-1) ………(ii) Calculate DeltaH for the ionisation of HF in H_(2)O .

C_(4)H_(10)+(13)/(2)O_(2)(g)rarr4CO_(2)(g)+5H_(2)O(l), DeltaH =- 2878 kJ DeltaH is the heat of……….of butane gas.

Given CaCl_(2)(s) +aq rarr CaCl_(2)(aq): DeltaH^(Theta) = 75 kJ mol^(-1) at 18^(@)C and CaCl_(2).6H_(2)O +aq rarr CaCl_(2)(aq), DeltaH^(Theta) 19 kJ mol^(-1) at 18^(@)C . Find the heat of hydration of CaCl_(2) to CaCl_(2). 6H_(2)O by H_(2)O (g) . The Heat of vaporisation of water may be taken as 2452 J mol^(-1) at 18^(@)C .

Whenever an acid is neutralised by a base, the net reaction is H^(o+)(aq)+overset(Theta)OH(aq)rarr H_(2)O(l),DeltaH =- 57.1 kJ Calculated the heat evolved for the following experiments? 0.50 mol of HCI solution is neutralised by 0.50mol of NaoH solution.

From the data at 25^(@)C : Fe_(2)O_(3)(s) +3C_(("graphite")) rarr 2Fe(s) + 3CO(g), DeltaH^(Theta) = 492.0 kJ mol^(-1) FeO(s) +C_(("graphite")) rarr Fe(s) CO(g), DeltaH^(Theta) = 155.0 kJ mol^(-1) C_(("graphite")) +O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 393.0 kJ mol^(-1) CO(g)+(1)/(2)O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 282.0 kJ mol^(-1) Calculate the standard heat of formation of FeO(s) and Fe_(2)O_(3)(s) .