The standard enthalpy of `Br_(2)(g)` is taken to be zero at standard conditions of `298K` and `1atm`.

What is standard enthalpy of formation

Standard enthalpy of formation is zero for

The standard enthalpy of diamond is zero at 298K and 1 atm pressure.

Standard enthalpy of formation is non zero for

Choose the reaction, for which the standard enthalpy of reaction is equal to the standard enthalpy of formation:

Standard molar enthalpy of formation of CO_(2) is equal to :

Find the value of Delta_(f) H^(@) for the reaction N_(2) O_(4) (g) + 3 CO(g) rarr N_(2) O (g) + 3 CO_(2) (g) Standard enthalpies of formation of CO(g), CO_(2) (g), N_(2) O (g) , and N_(2) O_(4) (g) are - 110, - 393, 81 , and 9.7 kJ mol^(-1) , respectively. Strategy : The standard enthalpy change of a reaction is equal to the sum of the standard molar enthalpie of formation of the products each multiplied by its stiochiometric coefficient in the balanced equation, minus the corresponding sum of the standard molar enthalpies of formation of the reactants

Standard heat of formation at 298K is arbitrarily taken to be zero for

The heat of formation is the change in enthalpy accompanying the formation of a substance fiom its elements at 298 K and 1 atm pressure. Since the anthalpies of elements are taken to be zero, the heat of formation (triangleH) of compounds

The voltage of the cell consisting of Li_((s)) and F_(2(g)) electrodes is 5.92 V at standard condition at 298 K. What is the voltage if the electrolyte consists of 2 M LiF. ("ln 2 = =0.693, R = 8.314 J K"^(-1)" mol"^(-1) and F = 96500" C mol"^(-1))