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One mole of a non-ideal gas undergoes a ...

One mole of a non-ideal gas undergoes a change of state `(2.0atm,3.0L,95K)rarr(4.0atm,5.0L,245K)`
With a change in internal energy `DeltaE=30L` atm. The change in enthalpy `(DeltaH)` in the process in `L`-atm is

A

`40.0`

B

`42.3`

C

`44.0`

D

Not defined because the pressure is not constant.

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AI Generated Solution

To find the change in enthalpy (ΔH) for the given process, we can use the relationship between change in enthalpy, change in internal energy, and the change in pressure-volume work. The formula we will use is: \[ \Delta H = \Delta E + \Delta (PV) \] ### Step 1: Identify the given values We have the following values from the problem statement: ...
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