When `1mol` of a monoatomic ideal gas at `TK` undergoes adiabatic change under a constant external pressure of `1atm`, changes volume from `1 L to 2L`. The final temperature (in K) would be

Options

A. `(T)/(2^(2//3))`
B. `T +(2)/(3xx0.0821)`
C. `T`
D. `T -(2)/(3 xx 0.0821)`

Explanation

To solve the problem of finding the final temperature of a monoatomic ideal gas undergoing an adiabatic change, we can follow these steps:

### Step 1: Understand the Adiabatic Process
In an adiabatic process, there is no heat exchange with the surroundings. The change in internal energy (ΔE) of the system is equal to the work done (ΔW) on or by the system.

### Step 2: Write the equations for the adiabatic process
For an ideal gas, the change in internal energy can be expressed as:
\[
...