`CsOH +HCI rarr CsCI +H_(2)O, DeltaH =- 13.4 kcal mol^(-1)……….(i)`
`CsOH +HF rarr CsF +H_(2)O, DeltaH =- 16.4 kcal mol^(-1) ………(ii)`
Calculate `DeltaH` for the ionisation of `HF` in `H_(2)O`.

Calculate heat of dissociation for acetic acid from the following data: CH_(3)COOH +NaOH rarr CH_(3)COONa +H_(2)O DeltaH = - 13.2 kcal H^(o+) +overset(Theta)OHrarr H_(2)O, DeltaH =- 13.7 kcal Also calculate heat of dissociation for NH_(4)OH if HCI +NH_(4)OH rarr NH_(4)CI +H_(2)O, DeltaH =- 12.27 kcal

HCI +NaOH rarr NaCI +H_(2)O, DeltaH =- 57.1 kJ mol^(-1) DeltaH is the heat of ……………….of HCI and NaOH solution.

Calculate the enthalpy of formation of sucrose (C_11H_22O_11) from the following data: (i) C_(12)H_(22)O_(11) + 12O_(2) rarr 12CO_(2) + 11 H_(2)O, DeltaH = -5200.7 kJ mol^(-1) (ii) C + O_(2) rarr CO_(2), DeltaH = -394.5 kJ mol^(-1) (iii) H_(2) + 1/2 O_(2) rarr H_(2)O, DeltaH = H_(2)O, DeltaH = -285.8 kJ mol^(-1) .

If 2AI(s) +1(1)/(2) O_(2)(g) rarr AI_(2)O_(3)(s), DeltaH =- 1667.8 kJ H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l), DeltaH =- 285.9 kJ Calculate DeltaH for the reaction AI_(2)O_(3)(s) rarr 2AI(s) +1(1)/(2)O_(2)(g)

Calculate the enthalpy of vaporisation for water form the following: H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(g),DeltaH =- 57.0 kcal H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l),DeltaH =- 68.3 kcal Also calculate the heat required to change 1g H_(2)O(l) to H_(2)O(g)

C_(2)H_(2) + 5/2 O_2(2) rarr 2CO_(2) + H_(2)O , Delta H = -310 kcal C + O_(2) rarr CO_(2) , " "Delta H = -94 kcal H_(2) + 1/2 O_(2) rarr H_(2)O, " " Delta H = -68 kcal On the basis of the above equations, DeltaH_(f) (enthalpy of formation) of C_2H_2 will be :

Given CaCl_(2)(s) +aq rarr CaCl_(2)(aq): DeltaH^(Theta) = 75 kJ mol^(-1) at 18^(@)C and CaCl_(2).6H_(2)O +aq rarr CaCl_(2)(aq), DeltaH^(Theta) 19 kJ mol^(-1) at 18^(@)C . Find the heat of hydration of CaCl_(2) to CaCl_(2). 6H_(2)O by H_(2)O (g) . The Heat of vaporisation of water may be taken as 2452 J mol^(-1) at 18^(@)C .

{:(C+O_(2)(g)rarrCO_(2)" ......(i),",DeltaH=-"393 kJ mol"^(-1)),(H_(2)+1//2O_(2)rarr H_(2)O", .....(ii)",DeltaH=-"287.3 kJ mol"^(-1)),(2CO_(2)+3H_(2)O rarr C_(2)H_(5)OH+2O_(2)" .....(iii)",DeltaH="1366.8 kJ mol"^(-1)):} Find the standard enthalpy of formation of C_(2)H_(5)OH(l)

Calculate heat of formation of KOH(s) using the following equations K(s) +H_(2)O(l) +aq rarr KOH(aq)+1//2 H_(2)O(g),DeltaH =- 48.0 kcal …(i) H_(2)(g) +2O_(2)(g) rarr H_(2)O(l),DeltaH =- 68.4 kcal …(ii) KOH(s) +(aq) rarr KOH(aq),DeltaH =- 14.0 kcal ....(iii)

Calculate heat of formation of KOH(s) using the following equations K(s) +H_(2)O(l) +aq rarr KOH(aq)+1//2 H_(2)(g),DeltaH =- 48.0 kcal …(i) H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l),DeltaH =- 68.4 kcal …(ii) KOH(s) +(aq) rarr KOH(aq),DeltaH =- 14.0 kcal ....(iii)