Compute the heat of formation of liquid methyl alcohol in kilojoule per mol using the following data. Heat of vaporisation of liquid methyl alcohol `=38kJ//mol`. Heat of formation of gaseous atoms from the elements in their standard states `:H=218kJ // mol, C=715kJ //mol, O=249kJ //mol.`
Average bond energies`:`
`C-H415kJ//mol, C-O 356kJ//mol, O-H 463kJ //mol.`

Explanation

To compute the heat of formation of liquid methyl alcohol (methanol, CH₃OH) using the provided data, we will follow these steps:

### Step 1: Write the Reaction for Formation of Methyl Alcohol
The formation of liquid methyl alcohol from its elements in their standard states can be represented as:
\[ \text{C (s)} + 2 \text{H}_2 \text{(g)} + \frac{1}{2} \text{O}_2 \text{(g)} \rightarrow \text{CH}_3\text{OH (l)} \]

### Step 2: Calculate the Heat of Formation of Gaseous Methyl Alcohol
We first need to find the heat of formation of gaseous methyl alcohol (CH₃OH(g)). The reaction for the formation of gaseous methyl alcohol is:
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