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Consider the following gases equilibrium...

Consider the following gases equilibrium given below:
(i) `N_(2)+3H_(2)hArr2NH_(3),"Eqm.Constant"=K_(1)`
(ii)`N_(2)+O_(2)hArr2NO, Eqm.constant=K_(2)`
(III) `H_(2)+(1)/(2)O_(2)hArrH_(2)O,Eqm.constant=K_(3)`
The equilibrium constant for the reaction ,`2NH_(3)+(5)/(2)O_(2)hArr3H_(2)O"in terms of" K_(1),K_(2)andK_(3)`will be :

A

`K_(1)K_(2)K_(3)`

B

`(K_(1)K_(2))/K_(3)`

C

`(K_(1)K_(3)^(2))/K_(2)`

D

`(K_(2)K_(3)^(3))/K_(1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(1)=([NH_(3)]^(2))/([N_(2)][H_(2)]), K_(2)=([NO]^(2))/([N_(2)][O_(2)]), K_(3)=([H_(2)O]^(2))/([N_(2)][O_(2)]^(1//2)),`
The equilibrium constant for
`2NH_(3)(g)+(5)/(2))_(2)(g)hArr2NO(g)+3H_(2)O(g)`
will be:
`K=([NO]^(2)[H_(2)O]^(3))/([NH_(3)]^(2)[O_(2)]^(5//2))=(K_(2)xxK_(3)^(3))/K_(1)`
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